Solve the Linear Equation:
1) x+2y=4
*to find the solution set of a equation involving two variables, solve for one of the variables in terms of the other variable.x=4-2y
*In this form, the variable y is free which means it can take any real value.The variable x is not free because it's value depends on the value assigned to y.
*To represent the infinite number of solutions of this equation, we use a third variable j called a parameter. By letting y=j, you can now represent the solution set.*Let y=j, j is a real number.
x=4-2j
Let j=1
2y=4-x
y=2-1/2x
x=2
y=1
The Solution Set is: (2,1) or (4,2).
2) 3x+2y-z=3
3x=3-2y-z
3
x=1-2/3y-1/3z
*Let y=s, s is a real number, z=t, t is a real number.
x=1-2/3s+1/3t
x=1-2/3(1)+1/3(1)=2/3
The Solution Set is: (2/3,1,1)
3) 1/2x-1/3y=1
(1/2x-1/3y=1)6
3x-2y=6
3x=6+2y
3
x=2+2y
3
*Let y=t, t is any real number.
x=2+2/3t
t=1
x=2+2/3t
x=2+2/3
x=8/3
The Solution Set is: (1, 8/3)
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